no that is not what i said.
stop limiting my words by your limitations.
my fault I'm not trying to misquote you...please clarify what you meant...
3.
do you understand superposition. do you understand how that is used in quantum computing?
until superpositions collapse probabilities do not unfold serially.
I'm having trouble reconciling how superposition and quantum computing tie into the discussion at hand. Can you clarify for me?
you make an assumption of serial events in the timespans that you use in your OP.
did I? well, here's the math used in the amoeba scenario calculations. Feel free to check it and let me know where assumptions were made....
Let
Tp represent the average time it would take for a usable protein of length
n to form.
Let
Tu represent the time it would take for the amoeba to haul the whole universe one atom per round trip.
Then the quantity
U (number of universes hauled) is
Tp ÷
Tu . If
Tp > Tu , then the amoeba can haul more than 1 universe. If
Tp < Tu, the amoeba can only haul a fraction of the universe.
Let’s look in detail at the factors involved in calculating
Tp and
Tu.
a = number of amino acid types used in proteins (20, only considering canonical types, since those are the only types that remained after the origin of life.)
n = number of amino acids in the target protein chain. Set as a constant, 150. (most protein chains range from 153 to 283 amino acids in length to we're being conservative.)
r = rate of chain formation in each set per year. At 1 per second, that’s 3.15 x 10^7 chains per year per set (60 seconds x 60 minutes x 24 hours x 365 days).
s = number of sets forming chains, limited by Carbon, Nitrogen, Oxygen on earth = 10^41
P = inverse probability of usable protein of length
n. For n = 150 amino acids, this is 10^164. This is the number of trials required, on average, in which to expect a success.
Tp is calculated as: P/r*s
d = diameter of the universe in inches. 90 billion light-years (a common estimate) is 3.4 x 10^28 inches.
u = number of atoms in the universe. We use 10^80 atoms as stated above.
i = rate amoeba travels in inches per year. We use 1 foot, which is 12 inches per year.
Tu is calculated as: 2d*u/
i
U = Tp / Tu is therefore: P/r⋅s / 2d*u/
i
Simplifying, this becomes P*I/2d*u*r*s
Substituting quantities, this results in:
U = 10^164*12 / (3.4*10^28)⋅(10^80)⋅(3.15*10^7)⋅(10^41)
= 5.6 x 10^7 = 56,000,000 universes (56 million)
It’s important to note that with the probability so vanishingly small, no amount of reasonable adjustment of the inputs will make a difference to the conclusion. For instance, if the waiting time for a protein to self-assemble was reduced drastically so that the amoeba could only haul one universe, or half a universe, chance still would be a wholly inadequate explanation.