YoungMasterGold
Rookie
x/y
If x = 6 and y = 2(1+2)
6/2(1+2) = 9
The answer is still 9, even if the problem is presented algebraically.
Um, no. Doing it in the way I described means you solve for "y" before reintroducing it into the equation. Therefore, y = 2(1+2) means y = 6. Then it's brought to bear in the equation. I assumed that was clear.
In any case, giving precedence to an operation means that it is taken care of first. One must get rid of the brackets first before division occurs. That's why the whole is: y = 2(1+2).
6 / 2(3)
is the exact same thing as
6 / 2 * 3
How would you solve that?
They are not the exact same thing. I think I've sussed out where the problem lies. It's false equivalence. If brackets and multiply meant exactly the same thing, you wouldn't need parentheses as operators.
To answer your question. 6/2(3) = 1, while 6/2*3 = 9.