Both answers are correct because the equation is written ambiguously.
Should have been:
(6÷2)*(1+2) = 9
or
6÷(2*(1+2)) = 1
/thread
co/sign
Both answers are correct because the equation is written ambiguously.
Should have been:
(6÷2)*(1+2) = 9
or
6÷(2*(1+2)) = 1
/thread
Which mathematician says its 1? Standard law of operation (or pemdas) states that division and multiplication are of the same priority, so how could it not be 9?
yo, the answer is 1.
you're not dumb, you're just uneducated on how to properly to do this question. what you do is follow the rules, and the rules are pemdas, and if you get that you get 1
i'm a math grad student so i hope you can take my word for this.
6/2(3) automatically makes the answer 1 if you do what's connected to the parentheses first as in Pemdas.
Of course if you apply what's in parentheses to 6/2 instead of merely 2, you get 9.
How are you getting 9 if you use pemdas?
6÷2(1+2)
6÷2(3)
6÷6=1
Yeah, but anything attached to a bracket becomes part of a whole in an operation. Think of it algebraically, the expression should be (in my interpretation): x/y. Where x is 6 and y is 2(1 + 2). Then again, one could argue it all comes down to syntax. . . or something.
How are you getting 9 if you use pemdas?
6÷2(1+2)
6÷2(3)
6÷6=1
Otherwise just go left to right. Example:
30 ÷ 5 × 3 = 6 × 3 =
18
(right)
30 ÷ 5 × 3 = 30 ÷ 15 =
2
(wrong)