@Blaxican707 Can i get you to go into detail about your sig and how your opportunities got better with each one
As in I could've got more on hourly rate doing Corp 2 Corp, but you have to handle how you pay all taxes versus W2 where its handled for you (you're still paying taxes either wayHow?
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Oh, i thought there was a loopholeAs in I could've got more on hourly rate doing Corp 2 Corp, but you have to handle how you pay all taxes versus W2 where its handled for you (you're still paying taxes either way)
@Blaxican707 Can i get you to go into detail about your sig and how your opportunities got better with each one
The CCNA will teach you the basics better than the network+ will. The CCNA will give you a strong understanding of TCP/IP, routing, switching, ACL's, subnets, and how these technologies work.
And don't shy away from a cert just because it's hard. The hard certs are typically the ones that make you the most money.
What aren't you getting exactly? There are a lot of techniques people use to subnet. You gotta understand the basics of an IP address 1stAnyone got any good meterial for subnetting? I've read the subnetting chapter of my net+ book over and over and I still cant quite grasp it.
What aren't you getting exactly? There are a lot of techniques people use to subnet. You gotta understand the basics of an IP address 1st
There are 8 bits in an octet. 1's and 0's binary form. For a total of 32 bits (remember this)
11111111 = 255
11111111.11111111.11111111.11111111 = 255.255.255.255
11111111.11111111.11111111.0 = 255.255.255.0 = /24
etc.
These are the subnet masks you can use
11111111 = 255
11111110 = 254
11111100 = 252
11111000 = 248
11110000 = 240
11100000 = 224
11000000 = 192
10000000 = 128
So when someone says a /22 (cidr notation) network. This is what they are referring to, 255.255.252.0
/30 = 255.255.255.252
/16 = 255.255.0.0
/26 = 255.255.255.192
etc.
If said find the subnet & broadcast mask of 192.168.32.129 255.255.255.192, Here's two ways you could do it...
1 - First you need to find out which octet you are working with. Look at the subnet mask. 192 is in the 4th octet of the subnet mask so in this scenario we are working with 4th octet of the ip address.
192.168.32.129
255.255.255.192
2 - Subtract 192 from 256 to find the block size
You use 256 because...that is the total numbers from 0-255
This will leave us with 64 which is your block size
3 - Count from 0 to find the subnet where 129 is in range of without going over
192.168.32.0
192.168.32.64
192.168.32.128
192.168.32.192
So we could see here 129 is between 128 and 192. Making it within the 128 subnet. The last number in the subnet is 191 which in this case would be the broadcast mask.
so 192.168.32.129 is in the
Subnet = 192.168.32.128
With a Broadcast Mask of = 192.168.32.191
Lets say they gave you that same problem but in CIDR notation 192.168.32.129 /26
Remember there are 8 bits in every octet right? So in total 8.8.8.8 = 32
What you can do is subtract the cidr notation from the next block size up
In this case
32 - 26 = 6
then use exponents...
2^6 = 64
The same block size we got earlier
I explained it like a coli goon but this is basically subnetting![]()
What aren't you getting exactly? There are a lot of techniques people use to subnet. You gotta understand the basics of an IP address 1st
There are 8 bits in an octet. 1's and 0's binary form. For a total of 32 bits (remember this)
11111111 = 255
11111111.11111111.11111111.11111111 = 255.255.255.255
11111111.11111111.11111111.0 = 255.255.255.0 = /24
etc.
These are the subnet masks you can use
11111111 = 255
11111110 = 254
11111100 = 252
11111000 = 248
11110000 = 240
11100000 = 224
11000000 = 192
10000000 = 128
So when someone says a /22 (cidr notation) network. This is what they are referring to, 255.255.252.0
/30 = 255.255.255.252
/16 = 255.255.0.0
/26 = 255.255.255.192
etc.
If said find the subnet & broadcast mask of 192.168.32.129 255.255.255.192, Here's two ways you could do it...
1 - First you need to find out which octet you are working with. Look at the subnet mask. 192 is in the 4th octet of the subnet mask so in this scenario we are working with 4th octet of the ip address.
192.168.32.129
255.255.255.192
2 - Subtract 192 from 256 to find the block size
You use 256 because...that is the total numbers from 0-255
This will leave us with 64 which is your block size
3 - Count from 0 to find the subnet where 129 is in range of without going over
192.168.32.0
192.168.32.64
192.168.32.128
192.168.32.192
So we could see here 129 is between 128 and 192. Making it within the 128 subnet. The last number in the subnet is 191 which in this case would be the broadcast mask.
so 192.168.32.129 is in the
Subnet = 192.168.32.128
With a Broadcast Mask of = 192.168.32.191
Lets say they gave you that same problem but in CIDR notation 192.168.32.129 /26
Remember there are 8 bits in every octet right? So in total 8.8.8.8 = 32
What you can do is subtract the cidr notation from the next block size up
In this case
32 - 26 = 6
then use exponents...
2^6 = 64
The same block size we got earlier
I explained it like a coli goon but this is basically subnetting![]()
I'm not sure what to do.
I want to go into programming. So far, I've been teaching myself Python for the past 2 months. I've finished one book (Think Python) and one video course. I'm currently reading another book (Byte of Python), going through Codecademy and I just started this humongous tutorial package I purchased on discount. shyt has 92 hours worth of lessonsEverything from Python, Ruby, PHP to Javascript and Angular.
My question though....I hear of people getting programming jobs within a year of learning. I'm wondering if I should try to pursue an A+ or Network+ cert to do something tech related in the meantime while I'm waiting to break into web development or is that a waste of time? Maybe I should do it just to hedge my bet. I don't know.