So in probability with replacement you get one million rolls before you lose?
Y'all keep talking about a theoretical possibility that may happen once in a trillion sequences
I was taking about you die if you get this wrong
So you're telling me a computer RNG set to 1 out of 100 will actually give you something besides 1 out of 100
Why would that be called 1 out of 100 of you truly had no way to predict how many rolls before a loss. On average.
Simple question.
Probability WITH replacement means you WILL NOT get an average of 1 loss per 100 rolls
An average of 1 loss per 100 rolls is factually irrelevant, you're still using the effect to try to explain the cause...
EVERY PUSH is independent of any other push. 1/100 is the chances of death every time you push the button. You don't use 1/100 for anything else; any other way you try to use 1/100 is wrong. I cannot explain that any clearer
Probability with replacement does not get you "one million rolls before you lose" it gives you the odds of "not losing" on a specified number of tries.
Examples:
The chance you push once and not die: 99% - net $1000
The chance you push 50 straight times without dying, 60% - net $50000
The chance you push 69 straight times without dying, approx 50% - net $69000
The chance you push 100 straight times without dying, approx 37% - net $100000
The chance you push 400 straight times without dying, approx 1.8% - net - $400000
It's not that difficult to understand, ANY attempt leaves you 1% likely to die. The odds of getting consistent non-death results decrease as your attempts increases but each individual push is the same. It's like the birthday game. Technically the odds are 1/365 of having any individual birthdate, but as you get a bigger group of people you don't have to get to 365 people to almost certainly end up with 2 people who share birthdays.