Brandon M.
City of Angels
show how yall got the answer...
i never took physics but am interested
i never took physics but am interested
--&& Daily Math/Physics Questions Thread &&--
- Thread starter TheAnointedOne
- Start date
TheAnointedOne
Superstar
Alright I believe some sufficient time has passed to explain my answer.
After 2 hours the thunderstorm clearly moved 30km 37 degrees north of east. We can express this in vector polar form: { 30 /_ 37 degrees }, where 30 is the magnitude and 37 is the angle.
We can convert this to component form as follow: v = { 30 * cos( 37 ), 30 * sin( 37 ) }
The question asks 'how far NORTH does the thunderstorm move?'
We can think of north as the positive y-axis. So therefore we need the y-component of the vector.
v.y = 30 * sin( 37 )
v.y = 30 * 0.60181
v.y = 18.05
v.y = 18 km
So the thunderstorm, after 2 hours, has traveled 18 kilometers north.
After 2 hours the thunderstorm clearly moved 30km 37 degrees north of east. We can express this in vector polar form: { 30 /_ 37 degrees }, where 30 is the magnitude and 37 is the angle.
We can convert this to component form as follow: v = { 30 * cos( 37 ), 30 * sin( 37 ) }
The question asks 'how far NORTH does the thunderstorm move?'
We can think of north as the positive y-axis. So therefore we need the y-component of the vector.
v.y = 30 * sin( 37 )
v.y = 30 * 0.60181
v.y = 18.05
v.y = 18 km
So the thunderstorm, after 2 hours, has traveled 18 kilometers north.
I solved it right just using properties of triangles instead of looking at it as vectors. the mistake I made was trying to do it in my head and not on paper
TheAnointedOne
Superstar
Difficulty: Easy
Category: Physics
Note: 2 part question
Fuel consumption of a car is the amount of fuel used per unit distance. It is customary to give fuel consumption in liters per 100 km (L/100 km). For example, the 2019 Austin Mini Cooper has a fuel consumption of 5.5 L/100 km, that is, it uses 5.5 liters of petrol per every 100 km driven.
a) If this car's petrol tank holds 40 L, how many tanks of petrol will you use to drive 1200 km?
b) You read in an English car magazine that the classic 1964 Austin Mini Cooper has an average estimated "mileage of 30.5 miles per gallon" (where 1 mile = 1.609 km is a British unit of distance and 1 gallon (UK) = 4.546 L is a British unit of capacity). Find the fuel consumption of this car and compare it with the 2019 model.
Category: Physics
Note: 2 part question
Fuel consumption of a car is the amount of fuel used per unit distance. It is customary to give fuel consumption in liters per 100 km (L/100 km). For example, the 2019 Austin Mini Cooper has a fuel consumption of 5.5 L/100 km, that is, it uses 5.5 liters of petrol per every 100 km driven.
a) If this car's petrol tank holds 40 L, how many tanks of petrol will you use to drive 1200 km?
b) You read in an English car magazine that the classic 1964 Austin Mini Cooper has an average estimated "mileage of 30.5 miles per gallon" (where 1 mile = 1.609 km is a British unit of distance and 1 gallon (UK) = 4.546 L is a British unit of capacity). Find the fuel consumption of this car and compare it with the 2019 model.
BaldingSoHard
Veteran
30 km.
Edit: Oh, how far north.... one sec.
Edit again: Thread already got to it... R Sin 37
MischievousMonkey
Gor bu dëgër
1) 1,65 tank(s)
12x100km=1200km -> 12x5.5=66L
66/40=1.65
66/40=1.65
9.26L per km?Mileage: 30.5x1.609=49.0745 km per gallon
49.0745:4.546=10.795 km per litre
=> (1/10.795) L per km
(1/10.795)=0.0926 L per km
0.0926x100=9.26 L per 100 km
That's the consumption of the English car, which consumes more fuel than the one from the first question.
49.0745:4.546=10.795 km per litre
=> (1/10.795) L per km
(1/10.795)=0.0926 L per km
0.0926x100=9.26 L per 100 km
That's the consumption of the English car, which consumes more fuel than the one from the first question.
Made me feel rusty as hell
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TheAnointedOne
Superstar
That was yesterday's question. Try your hand at today's question.
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TheAnointedOne
Superstar
I would try to prepare for that shyt now honestly. I wasn't prepared and failed that shyt when I was in college.
Rembrandt
the artist
For real. Now is the best time to try to get the foundations built.
Physics | Science | Khan Academy
Shout out to one of the GOAT sites for math refresher and getting basics down.
TheAnointedOne
Superstar
You should do practice problems too. Just sitting there and watching his videos isn't enough.
Drip Bayless
Superstar
Got 9.26 km/100 L
Edit: 9.26 is correct for the imperial gallon (4.546 L) the US gallon is 3.785 L which makes it 7.71 L/100 km
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TheAnointedOne
Superstar
1) 1,65 tank(s)
2)12x100km=1200km -> 12x5.5=66L
66/40=1.65
Mileage: 30.5x1.609=49.0745 km per gallon
49.0745:4.546=10.795 km per litre
=> (1/10.795) L per km
(1/10.795)=0.0926 L per km
0.0926x100=9.26 L per 100 km
That's the consumption of the English car, which consumes more fuel than the one from the first question.
Made me feel rusty as hell
A) So the car's petrol tank holds 40 L
Its fuel consumption is 5.5 L/100 km.
How many petrol tanks will it need for 1200 kilometers? Easy.
Multiply the fuel consumption by 12 (because 100 * 12 = 1200 km)
5.5*12 = 66
100*12 = 1200 km
After 1200 kilometers it will use 66 liters. It's tank can only hold 40 L
66 / 40 = 1.65 tank(s) is needed for 1200 km
B)
1 mile = 1.609 km
1 gallon = 4.546
"mileage of 30.5 miles per gallon"
30.5 miles per gallon
30.5*1.609 = 49.0745 km
"mileage of 49.0745 kilometers per gallon"
1 gallon = 4.546 L
"mileage of 49.0745 kilometers per 4.546 L"
4.546 L/49.0745 km
L/100 km
x = 100 / 49.0745
x = 2.0377
y = 4.546 * x
y = 4.546 * 2.0377
y = 9.2634
y = 9.26 L
9.26 L/100 km*
* - Unfortunately the book says that the answer is 9.4 L/100 km. Not sure how they got that. Could be a publishing error (some times they would publish newer editions which corrects such things)
Its fuel consumption is 5.5 L/100 km.
How many petrol tanks will it need for 1200 kilometers? Easy.
Multiply the fuel consumption by 12 (because 100 * 12 = 1200 km)
5.5*12 = 66
100*12 = 1200 km
After 1200 kilometers it will use 66 liters. It's tank can only hold 40 L
66 / 40 = 1.65 tank(s) is needed for 1200 km
B)
1 mile = 1.609 km
1 gallon = 4.546
"mileage of 30.5 miles per gallon"
30.5 miles per gallon
30.5*1.609 = 49.0745 km
"mileage of 49.0745 kilometers per gallon"
1 gallon = 4.546 L
"mileage of 49.0745 kilometers per 4.546 L"
4.546 L/49.0745 km
L/100 km
x = 100 / 49.0745
x = 2.0377
y = 4.546 * x
y = 4.546 * 2.0377
y = 9.2634
y = 9.26 L
9.26 L/100 km*
* - Unfortunately the book says that the answer is 9.4 L/100 km. Not sure how they got that. Could be a publishing error (some times they would publish newer editions which corrects such things)
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TheAnointedOne
Superstar
I might switch it up and do a calculus problem tomorrow.
MischievousMonkey
Gor bu dëgër
I was like breh my shyt is WITHERED lol
TheAnointedOne
Superstar
Softball one
Difficulty: Easy
Category: Calculus
lim {x -> 1} ( x^2 + x - 2 ) / ( x - 1 )
Note: It reads 'limit as x approaches one'.
'^' this symbol signifies exponent. So 'x^2' reads 'x to the 2nd power'.
'/' signifies division. So '3 / 2' reads '3 divided by 2'
Difficulty: Easy
Category: Calculus
lim {x -> 1} ( x^2 + x - 2 ) / ( x - 1 )
Note: It reads 'limit as x approaches one'.
'^' this symbol signifies exponent. So 'x^2' reads 'x to the 2nd power'.
'/' signifies division. So '3 / 2' reads '3 divided by 2'
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