Any math majors or mathematicians?

[Danycacks]

too much english and not enough math you two are doing ... no good ... no good

Numbers turned to letters and proofs breh. We off that

ok, using a rectangle abcd, and the intersection of the diagonals being E:

A. B
E
D. C

I used alt. Interior angles to prove
<Dac=<BCA
<adb=<cbd

You know from opposite sides that
AD=BC
So the two triangles in the inside ADE=BEC from the ASA postulate.

If those two angles are congruent, then their legs are as well, so
AE=EC=DE=EB
And that means for the diagonals:
AE+EC=AC
DE+EB=DB
Must also be equal?

Vertical angles are equal as well, maybe use that? It's been awhile since I did this lol.

Edit: fukk it, I have no idea lol.

Once you have the two triangles with two equal sides and both sharing the same angle (right angle). Can't you use this SAS (Side Angle Side postulate for proving congruent triangles ...) which proves that they are congruent and if they are congruent then the two diagonals must be equal as well

Double.

Thanks brehs!

 

[Gallo]

For now, I gotta prove that the diagonals on a rectangle are equal using congruent angles, alternate interior/exterior angles, the ASA, SSS, AAS theories and the pons asinorum (if thats how you spell it). Dont use the pythagorean theorem.

Use similar/congruent triangles or prove the two diagonals intersect at a point that bisects both of them, then since the bisected diagonals are the sides of two congruent triangles, they must have equal lengths.

 

[Brown_Pride]